Respuesta :
well, we know the slope-intercept is y=5x-3 , now [tex]\bf y=\stackrel{slope}{5}x\stackrel{y-intercept}{-3}[/tex].
reason why is called the slope-intercept form, so, the slope is 5, and we know the line runs through -2,-13, thus
[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -2 &,& -13~) \end{array} \\\\\\ % slope = m slope = m\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-13)=5[x-(-2)] \\\\\\ y+13=5(x+2)[/tex]
reason why is called the slope-intercept form, so, the slope is 5, and we know the line runs through -2,-13, thus
[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -2 &,& -13~) \end{array} \\\\\\ % slope = m slope = m\implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-13)=5[x-(-2)] \\\\\\ y+13=5(x+2)[/tex]
