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The sum of twice a first number and 4 times the second number is 20. The first number is 3 times the second. Find the numbers

The sum of twice a first number and 4 times the second number is 20 The first number is 3 times the second Find the numbers class=

Respuesta :

jushmk
Let the first and second numbers be x and y respectively.

Then,
2x+4y = 20
x=3y

Substituting for x,

2(3y)+4y=20 => 6y+4y =20 =>10y=20 =>y =20/10 = 2
And therefore, x=3y = 3*2 = 6

Therefore,
First number = 6 and second number =2

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