Let N be the numerator, D be the denominator
[tex] \frac{N}{D} [/tex]
if its numerator is decreased by 50%
[tex] N - \frac{50}{100}N [/tex] ==> (this will be the numerator part)
if its denominator is decreased by 25%
[tex] D - \frac{25}{100}D [/tex] ==> (this will be the denominator part)
I try to separate them out, so it's easier to see the problem.
[tex] N - \frac{50}{100}N = \frac{100N}{100} - \frac{50N}{100} = \frac{50N}{100} [/tex]
[tex] D - \frac{25}{100}D = \frac{100D}{100} - \frac{25D}{100} = \frac{75D}{100}[/tex]
[tex] \frac{\frac{50N}{100}}{\frac{75D}{100}} = \frac{50N}{100} * \frac{100}{75D}[/tex]
[tex] \frac{50N}{75D} = \frac{2}{3}(\frac{N}{D})[/tex] by this, you can understand that
[tex] \frac{2}{3}(\frac{N}{D})[/tex] as 66.6% of N/D because 2/3 is 0.666666.... The answer should be 66.7% if you round them up.
