The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C

It is so simple and direct substitution in the formula of :
C= Q/ m ΔT
when C is specific heat constant
and Q is heat energy of joul
and m is the mass
and ΔT is the change in temperature
and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:
∴C = 293/(25*15)
= 0.78 J/g-°C
∴ 0.78 J/g-°C is the correct answer

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bhaddiebykeyiah bhaddiebykeyiah · Answer 2 · 2022-03-23T18:40:59+01:00

bhaddiebykeyiah bhaddiebykeyiah

23-03-2022

Answer:

0.78 J/g-°C is the correct answer

Explanation:

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The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT. a.) 0.13 J/g-°C b.) 0.20 J/g-°C c.) 0.78 J/g-°C d.) 0.46 J/g-°C

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The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

a.) 0.13 J/g-°C

b.) 0.20 J/g-°C

c.) 0.78 J/g-°C

d.) 0.46 J/g-°C