we know that
[volume of right circular cylinder]=pi*r²*h
Vo=pi*r²*h--------------> original volume
Vo= 22 cm³
if twice the radius and half the height
r1=2*r
h1=h/2
then
V1=pi*ri²*h1
substituting
V1=pi*(2*r)² *(h/2)----------->V1= pi*4*r² *h/2-----------> V1=2*pi*r² *h
V1=2*[pi*r² *h]------------> V1=2Vo
V1=2*22=44 cm³
the answer is 44 cm³
