If the final concentration of NOBr = 0.250M Change in concentration of NOBr = +0.250 M Change in concentration of NO = -0.250 M Change is concentration of Br2 = -0.125 M ( since number of moles of Br2 is 0.5 times the number of mole of NOBr) Final concentration of NO = 0.400-0.250 = 0.150 M Final concentration of Br2 = 0.245 - 0.125 M = 0.0120 M Therefore; Kc = conc (NOBr)^2/ ((conc NO)^2 ×(conc (Br2) = (0.250²)/(0.150²×0.120) = 23.148 = 23.1 mol/dm³
