Answer:
B) 1 must be the root of the polynomial [tex]3x^2+x-4[/tex].
Step-by-step explanation:
We are given that polynomial [tex]3x^2+x-4[/tex] is being divided by factor (x-1).
It is also said that when David perform the mathematical operation it gives remainder 0 .
Remainder 0 represents that divisor (x-1) is a factor polynomial [tex]3x^2+x-4[/tex].
As x-1 is a factor of the given ploynomial, we can get one of the root of by setting it equal to 0 and solve for x.
Therefore,
x-1=0
Adding 1 on both sides, we get
x-1+1= 0+1
x=1.
Therefore, 1 must be the root of the polynomial [tex]3x^2+x-4[/tex].
