Respuesta :
Answer:
By SSS congruency rule ΔABD ≅ ΔCBD
Step-by-step explanation:
Given parallelogram ABCD with diagonal BD. we have to prove that ABD is congruent with triangle CDB.
In ΔABD and ΔCBD
AD=BC (Opposite sides of parallelogram)
AB=DC (Opposite sides of parallelogram)
DB=DB (common)
All three sides are equal.
Hence, By SSS congruency rule ΔABD ≅ ΔCBD
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