if ∆GFE ~ ∆CBE, find the value of x

The value of x given that ∆GFE is congruent to ∆CBE is; x = 9
We are given that;
∆GFE is congruent to ∆CBE.
Now, the corresponding sides of both triangles are;
We see that;
FE = 4x - 1
BE = x + 5
CE = 24
GE = 60
Thus,by similar triangles, we have;
(4x - 1)/(x + 5) = 60/24
>> (4x - 1)/(x + 5) = 5/2
>> 2(4x - 1) = 5(x + 5)
>> 8x - 2 = 5x + 25
>> 8x - 5x = 25 + 2
3x = 27
x = 27/3
x = 9
Read more about Similar triangles at; https://brainly.com/question/14285697