Select all of the quadrants that the parabola whose equation is x = y² + 1 occupies.

I
II
III
IV

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When you solve the equation x = y^2 + 1, you get this line.

(photo)

The line graphed takes both quadrants I & IV, or 1 & 4.

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athleticregina athleticregina · Answer 2 · 2019-04-18T06:04:51+02:00

Answer:

Option (a) and (d ) is correct.

The parabola whose equation is [tex]x=y^2+1[/tex] occupies I and IV quadrant.

Step-by-step explanation:

Given : Equation of parabola as [tex]x=y^2+1[/tex]

We have to choose the quadrants that the parabola whose equation is [tex]x=y^2+1[/tex] occupies.

Consider the given equation [tex]x=y^2+1[/tex]

Since, y can take both negative and positive values.

So y can be both positive and negative.

But [tex]y^2[/tex] will be positive always as square of a number whether positive or negative will be positive always.

Thus, x will be positive always.

And we know when both x and y are positive then the point lies in first quadrant and when x is positive and y is negative then the point lies in fourth quadrant.

Thus, The parabola whose equation is [tex]x=y^2+1[/tex] occupies I and IV quadrant.

Select all of the quadrants that the parabola whose equation is x = y² + 1 occupies. I II III IV

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Select all of the quadrants that the parabola whose equation is x = y² + 1 occupies.

I
II
III
IV