Answer : The hybridization of central atom in [tex]CCl_4[/tex] is [tex]sp^3[/tex] and the shape of [tex]CCl_4[/tex] molecule is, tetrahedral.
Explanation :
Formula used :
[tex]\text{Number of electron pair}=\frac{1}{2}[V+N-C+A][/tex]
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
Now we have to determine the hybridization of the given molecule.
The given molecule is, [tex]CCl_4[/tex]
In this molecules, the central atom will be carbon not chlorine because carbon is less electronegative atom than the chlorine.
[tex]\text{Number of electrons}=\frac{1}{2}\times [4+4]=4[/tex]
The number of electron pair are 4 that means the hybridization will be [tex]sp^3[/tex] and the electronic geometry of the molecule will be tetrahedral.
Hence, the hybridization of central atom in [tex]CCl_4[/tex] is [tex]sp^3[/tex] and the shape of [tex]CCl_4[/tex] molecule is, tetrahedral.
