What is the current in a series circuit that has two resistors (4.0 ohms and 7.5 ohms) and a power source of 9.0 volts? A . 2.6 amps B . 12 amps C . 1.6 amps D . 0.78 amps

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C is your answer.
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Answer:

I = V / (R1 +R2)

I= 9 V / (4 + 7.5) Ohms

I = 9 V / 11.5 Ohms

I = 0.78 A

Step-by-step explanation: