Answer:
[tex]x=-1\text{ or }x=1[/tex]
Step-by-step explanation:
We have been given an equation [tex]2x^2=2[/tex]. We are asked to find the solutions of our given equation.
First of all, let us divide both sides of our equation by 2.
[tex]\frac{2x^2}{2}=\frac{2}{2}[/tex]
[tex]x^2=1[/tex]
Upon taking square root of both sides of our equation we will get,
[tex]x=\sqrt{1}[/tex]
[tex]x=\pm 1[/tex]
[tex]x=-1\text{ or }x=1[/tex]
Therefore, [tex]x=-1\text{ or }x=1[/tex] are two solutions for our given function.
