What is the length of side AB of the triangle?
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Answer:
the distance is 4.47 linear units
Step-by-step explanation:
Hello, I can help you with this.
you can solve this by using the distance between two points formula.
Step 1
let's remember the distance between two points formula.
Let
[tex]P1(x_{1},y_{1})\\P2(x_{2},y_{2})[/tex]
the distance between P1 and P2 is given by:
[tex]d=\sqrt{(x_{2}-x_{1}) ^{2} +(y_{2}-y_{1}) ^{2}} \\[/tex]
Step 2
all you have to do is put the values into the equation
Let
P1(2,1)
P2(4,5)
then
[tex]x_{1}=2\\y_{1}=1\\x_{2}=4\\y_{2}=5\\[/tex]
[tex]d=\sqrt{(x_{2}-x_{1}) ^{2} +(y_{2}-y_{1}) ^{2}} \\\\d=\sqrt{(4-2) ^{2} +(5-1) ^{2}} \\\\d=\sqrt{(2) ^{2} +(4) ^{2}} \\\\d=\sqrt{20}\\ d=4.47[/tex]
so the distance between A and B is 4.47
I hope it helps , have a great day.