Determine the number of real solutions to each quadratic equation Homework question. Not a test or exam

Given
Quadratic Equation
[tex]r^2+18r+81=0[/tex]Find
Number of real solutions
Explanation
The value of discriminant tells us the nature of solutions of a given equation.
if D>0 , then the equation has two distinct real roots.
if D=0, then the equation has two equal real roots.
if D<0, then the equation has two conjugated complex roots.
so,
[tex]r^2+18r+81=0[/tex]discriminant =
[tex]\begin{gathered} D=b^2-4ac \\ D=(18)^2-4\times1\times81 \\ D=324-324 \\ D=0 \end{gathered}[/tex]here D =0 , then it has two equal real solution.
Final Answer
Hence , it has two equal real solutions