Given
100th term of an arithmetic sequence is 595 and common difference , d = 6
Find
First three terms of arithmetic sequences.
Explanation
As we know the general nth term of an arithmetic sequence is given by
[tex]a_n=a+(n-1)d[/tex]
we have given 100th term = 595 , so
[tex]\begin{gathered} a_{100}=a+(100-1)6 \\ 595=a+99\times6 \\ 595-594=a \\ a=1 \end{gathered}[/tex]
so , first term = 1
second term = a + 6 = 7
third term = a + 2d = 1 +2*6 = 13
Final Answer
Therefore , the first terms of an arithmetic sequences are
[tex]a_1=1,a_2=7,a_3=13[/tex]
