Answer:
[tex]\text{amplitude: 1, period: }\pi[/tex]
Explanation:
Given the function in the attached image;
[tex]f(t)=\sin 2t[/tex]
Comparing to the general form of periodic equations.
[tex]f(t)=A\sin B(t+C)+D[/tex][tex]\begin{gathered} A=\text{ Amplitude} \\ A=1 \end{gathered}[/tex][tex]\begin{gathered} \text{Period =}\frac{2\pi}{B} \\ \text{ from the equation B = 2;} \\ \text{ Period = }\frac{2\pi}{2}=\pi \end{gathered}[/tex]
Therefore;
[tex]\text{amplitude: 1, period: }\pi[/tex]
