Given:
The length of the bases of the trapezoid
[tex]\begin{gathered} KL=a=12cm \\ \\ OM=b=16cm \end{gathered}[/tex]
Height of the trapezoid:
[tex]LN=h=8cm[/tex]
Required:
The area of trapezoid KLMO
Explanation:
The formula for area of trapezoid is given by
[tex]A(trapezoid)=\frac{a+b}{2}\times h[/tex]
Substituting the given values in the above equation we get
[tex]\begin{gathered} A(trapezoid\text{ }KLMO)=\frac{a+b}{2}\times h \\ \\ A(trapezoid\text{ }KLMO)=\frac{12+16}{2}\times8=\frac{28}{2}\times8=14\times8=112cm^2 \end{gathered}[/tex]
Final answer:
The area of trapezoid KLMO is 112 sq.cm
