ANSWER
[tex]\begin{gathered} A=\frac{1}{4} \\ B=\frac{1}{2} \\ C=\frac{1}{4} \end{gathered}[/tex]
EXPLANATION
From the given data;
Event A; Alternating even and odd numbers means;
EOE and OEO
Number of favourable outcome is 2 while number of possible outcome is 8
Hence, the probability of Event A IS;
[tex]\begin{gathered} Prob(A)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]
In Event B; More even numbers than odd means having;
EEE,OEE,EEO and EOE
[tex]\begin{gathered} EEE,OEE,EEOandEOE \\ Prob(B)=\frac{4}{8} \\ =\frac{1}{2} \end{gathered}[/tex]
For Event C; an even number on both the first and the last rolls;
EEE and EOE
[tex]\begin{gathered} EEEandEOE \\ Prob(C)=\frac{2}{8} \\ =\frac{1}{4} \end{gathered}[/tex]
