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Suppose that the amount in grams of a radioactive substance present at time t (in years) is given by A(t) = 800e -0.86t. Find the rate of change of the quantity present at the time when t = 5. O 9.3 grams per year 0 -72.7 grams per year 0-9.3 grams per year O 72.7 grams per year

Suppose that the amount in grams of a radioactive substance present at time t in years is given by At 800e 086t Find the rate of change of the quantity present class=

Respuesta :

Let's begin by listing out the information given to us:

[tex]\begin{gathered} A\mleft(t\mright)=800e^{-0.86t} \\ \Delta A(t)=-0.86\cdot800e^{-0.86t} \\ \Delta A(5)=-0.86\cdot800e^{-0.86\mleft(5\mright)} \\ A(5)=-9.34 \\ A(5)=-9.3g\text{ / year} \end{gathered}[/tex]

Hence, the correct option is the third option -9.3 grams per year

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