To answer this question we will use the following properties of exponents:
[tex]\begin{gathered} (\frac{a}{b})^x=\frac{a^x}{b^x}, \\ a^x*a^y=a^{x+y}. \end{gathered}[/tex]
Now, notice that:
[tex]9=\frac{36}{4}.[/tex]
Therefore:
[tex]9^x=(\frac{36}{4})^x.[/tex]
Using the first property we get that:
[tex]9^x=\frac{36^x}{4^x}.[/tex]
Now, notice that x=1+x-1, then:
[tex]9^x=9^{1+x-1}=9*9^{x-1}.[/tex]
Answer: Options A, E, and F.
