We must substitute each pair into our equation:
A. If we substitute point (1,1), we have
[tex]\begin{gathered} 1=-6(1)+7 \\ 1=-6+7 \\ 1=1 \end{gathered}[/tex]
then, this point is a solution.
B. If we substitute point (-1,1), we have
[tex]\begin{gathered} 1=-6(-1)+7 \\ 1=6+7 \\ 1=13\text{ !!!} \end{gathered}[/tex]
this means that this point is not a solution.
C. If we substitute point (-6,7), we have
[tex]\begin{gathered} 7=-6(-6)+7 \\ 7=36+7 \\ 7=43\text{ !!!} \end{gathered}[/tex]
this means that this point is not a solution.
D. If we substitute point (3,-11), we have
[tex]\begin{gathered} -11=-6(3)+7 \\ -11=-18+7 \\ -11=-11 \end{gathered}[/tex]
then, this point is a solution.
Therefore, the solutions are option A and D
