can you solve this please this is the link you need (i think): https://contentstore.ple.platoweb.com/content/GeoGebra.v5.0/CCSS_A2.02_Slope_of_Parallel_and_Perpendicular_Lines.html
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Part A is. The slope of two parallel lines are the same, therefore:
Part B: You can find the points remember that m1=m2
[tex]m_{ab}=\frac{y_2-y_1}{x_2-x_1}=\frac{3-(-1)}{-3-(-1)}=\frac{4}{-2}=-2[/tex]the slope that passes through c will be the same: -2.
Using the point C(1,2) and the slope- intercept point.
[tex]\begin{gathered} y=mx+b \\ 2=(-2)*1+b \\ b=2+2=4 \\ y=-2x+4 \end{gathered}[/tex]The equation for the line parallel to AB is: y=-2x+4, where the y-intercept will be the point: (0,4)
Part C. The slope of both lines are the same because they have the same inclination.