Given:
Given data points are (950,100) and (1000,40).
Required:
To find the linear model for this data.
Explanation:
The standard form of linear equation is
[tex]y=mx+b[/tex]
Where
[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ \\ m=\frac{40-100}{1000-950} \\ \\ m=-\frac{60}{50} \\ \\ m=-\frac{6}{5} \end{gathered}[/tex]
Now
[tex]y=-\frac{6}{5}x+b[/tex]
Now we have to find b using the points (950,1000), we get
[tex]\begin{gathered} 1000=-\frac{6}{5}(950)+b \\ \\ 1000=-6\times190+b \\ \\ 1000=-1140+b \\ \\ b=1000+1140 \\ \\ b=2140 \end{gathered}[/tex][tex]y=-\frac{6}{5}x+2140[/tex]
Final Answer:
[tex]y=-\frac{6}{5}x+2,140[/tex]
