Three math classes at Sunview High School collected the most box tops for a school fundraiser, and so they won a $600 prize to share among them. Mr. Aceves’ class collected 3,760 box tops, Mrs. Baca’s class collected 2,301, and Mr. Canyon’s class collected 1,855. How should they divide the money so that each class gets the same fraction of the prize money as the fraction of the box tops that they collected?

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MastonO693924 MastonO693924 · Answer 1 · 2022-11-03T12:24:16+01:00

The total amount fundraised is given as follows:

[tex]3760+2301+1855=7916\text{ box tops}[/tex]

The proportion of Mr. Aceves' class collected is given as follows:

[tex]\frac{3760}{7916}\text{ box tops}[/tex]

The proportion of Mr. Baca's class collected is given as follows:

[tex]\frac{2301}{7916}\text{ box tops}[/tex]

The proportion of Mr. Canyon's class is given as follows:

[tex]\frac{1855}{7916}\text{ box tops}[/tex]

Now compute the amount for Mr. Aceves' class is given as follows:

[tex]\frac{3760}{7916}\times600\approx284.99[/tex]

Again, compute the amount for Mr. Baca's class is given as follows:

[tex]\frac{2301}{7916}\times600\approx174.41[/tex]

Again, compute the amount for Mr. Canyon's class is given as follows:

[tex]\frac{1855}{7916}\times600\approx140.60[/tex]

As a result, $284.99 will go to Mr. Aceve's class, $174.41 will go to Mr. Baca's class, and $140.60 will go to Mr. Canyon's class.