Find the probability that the respondent will choose "somewhat likely". Divide the number of respondents who chose the option by the total number of respondents.
[tex]\begin{gathered} P(SL)=\frac{290}{\~likely)=\frac{290}{210+290+340+80+80}} \\ =\frac{290}{1000} \\ =0.29 \end{gathered}[/tex]
Since we need to find the probability of the complement of "somewhat likely", subtract the obtained probability from 1.
[tex]\begin{gathered} P(notSL)_{}=1-0.29 \\ =0.71 \end{gathered}[/tex]
