Given the function:
[tex]f\mleft(x\mright)=(x+4)^2\left(x-2\right)^5(x-1\rparen[/tex]The x-intercept iswhen y =0, so:
[tex]\begin{gathered} x+4=0 \\ x+4-4=0-4 \\ x=-4 \\ \end{gathered}[/tex]And
[tex]\begin{gathered} x-2=0 \\ x-2+2=0+2 \\ x=2 \end{gathered}[/tex]And
[tex]\begin{gathered} x-1=0 \\ x-1+1=0+1 \\ x=1 \end{gathered}[/tex]Therefore, the x-intercepts are:
(-4, 0), (2, 0) and (1, 0)
Answer:
(-4, 0), (2, 0) and (1, 0)
