Use Law of sines to solve for this problem. Round your answer to the nearest TENTH.
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We will have the following:
AB:
[tex]\begin{gathered} \frac{15}{sin(70)}=\frac{AB}{sin(45)}\Rightarrow AB=\frac{15sin(45)}{sin(70)} \\ \\ \Rightarrow AB=11.28730979...\Rightarrow AB\approx11.3 \end{gathered}[/tex]So, the measure of segment AB is approximately 11.3 units.
BC:
[tex]\begin{gathered} \frac{BC}{sin(65)}=\frac{15}{sin(70)}\Rightarrow BC=\frac{15sin(65)}{sin(70)} \\ \\ \Rightarrow BC=14.46708903...\Rightarrow BC\approx14.5 \end{gathered}[/tex]So, the measure of segment BC is approximately 14.5 units.