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This circle is centered at the point (2, 6), and the length of its radius is 4. Whatis the equation of the circle?-101010(2, 6),10A. (x-6)2 + (y-2)² = 16B. (x + 2)2 + (y+ 6)² = 4C. (²-2) +(²-6) = 4²D. (x-2)2+(-6)² = 16

This circle is centered at the point 2 6 and the length of its radius is 4 Whatis the equation of the circle1010102 610A x62 y2 16B x 22 y 6 4C 2 6 4D x226 16 class=

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ANSWER

D. (x - 2)² + (y - 6)² = 16

EXPLANATION

The equation of a circle in standard form is,

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where r is the radius and (h, k) is the center of the circle.

In this case, we have a circle with center at (2, 6) and radius of 4, so the equation is,

[tex]\begin{gathered} (x-2)^2+(y-6)^2=4^2 \\ \\ (x-2)^2+(y-6)^2=16 \end{gathered}[/tex]

Hence, the equation of the circle is (x - 2)² + (y - 6)² = 16.

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