Question
[tex]\sqrt[]{18x^3}\text{ }\frac{.}{.}\text{ }\sqrt[]{9x}[/tex][tex]\begin{gathered} =\text{ }\frac{\sqrt[\square]{9\text{ }\times\text{ 2 }\times x^2\text{ }\times\text{ x }}}{\sqrt[\square]{9x}} \\ =\text{ }\frac{3x\sqrt[\square]{2x}}{3\sqrt[\square]{x}} \\ \text{Next, rationalize } \\ =\text{ }\frac{3x\sqrt[\square]{2x}}{3\sqrt[\square]{x}}\text{ }\times\text{ }\frac{3\sqrt[\square]{x}}{3\sqrt[\square]{x}} \\ =\text{ }\frac{9x\text{ }\times\text{ }\sqrt[\square]{2x^2}}{9x} \\ =\text{ }\sqrt[\square]{2x^2} \\ =\text{ x}\sqrt[]{2} \end{gathered}[/tex]
Final answer is Option A
