Write the equation of the line passing through point (4, -2) and perpendicular to y = 4x + 2
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In our case, we can note that the slope m is the coefficient of the variable x, that is,
[tex]m=4[/tex]A perpendicular line must have a negative reciprocal slope, that is,
[tex]\begin{gathered} M=-\frac{1}{m} \\ then \\ M=-\frac{1}{4} \end{gathered}[/tex]then, the searched line has the form
[tex]y=-\frac{1}{4}x+b[/tex]Now, we can find b by means of the given point (4,-2). Then, by replacing this point into the last equation, we get
[tex]-2=-\frac{1}{4}(4)+b[/tex]which gives
[tex]-2=-1+b[/tex]and by moving -1 to the left hand side, we have
[tex]\begin{gathered} -2+1=b \\ -1=b \\ or\text{ quivalently,} \\ b=-1 \end{gathered}[/tex]Therefore, the perpendicular line is
[tex]y=-\frac{1}{4}x-1[/tex]which corresponds to option b