Answer:
The margin of error associated with the true population mean is;
[tex]\pm4.652\text{ ounces}[/tex]
Explanation:
Given the sample size as;
[tex]n=30[/tex]
standard deviation as;
[tex]\sigma=13[/tex]
the mean;
[tex]\bar{x}=33[/tex]
And confidence interval of 95%;
[tex]Z=1.96[/tex]
The Margin of Error MOE, can be calculated using the formula;
[tex]\text{MOE}=\pm Z\times\frac{\sigma}{\sqrt[]{n}}[/tex]
Substituting the given values;
[tex]\text{MOE}=\pm1.96\times\frac{13}{\sqrt[]{30}}=\pm4.652[/tex]
Therefore, the margin of error associated with the true population mean is;
[tex]\pm4.652\text{ ounces}[/tex]
