Please help me with this question on my homework. I've been stuck for a while
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[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$360\\ P=\textit{original amount deposited}\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &8 \end{cases} \\\\\\ 360 = (P)(0.06)(8)\implies \cfrac{360}{(0.06)(8)}=P\implies 750=P[/tex]