Use the points (0, 4) and (-2, 3) to find the slope of the line and give the equation of this line.
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Answer:
Choice C: [tex]m=\frac{1}{2}; y=\frac{1}{2} x+4[/tex]
Step-by-step explanation:
To find your slope do:
[tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
[tex]\frac{3-4}{-2-0}=\frac{-1}{-2} =\frac{1}{2}[/tex]
that's how you get 1/2
4 is just the y-int.
The required equation of line passes through (0, 4) and (-2, 3), has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.
The equation is the values of two expressions that are equal.
The slope of the line is the tangent angle made by the line with horizontal. i.e. m =tanx where x in degrees.
The slope of the equation line passing through (0, 4) and (-2, 3)
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\m = (3 - 4) / (-2-0)\\m = -1/-2\\m = 1/2[/tex]
Strand form of the equation of the line,
[tex]y-y_1 = m(x-x_1)[/tex]
Putting values in the standard form of the equation of the line.
y - 4 = 1/2 * (x - 0)
y = 1/2 * x + 4
[tex]y = \frac{1}{2} x + 4[/tex]
Thus, the required equation of line passes through (0, 4) and (-2, 3), has slope of m = 1/2 , is y = 1/2x + 4. Option C is correct.
Learn more about slopes here:
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