[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Refer to the attachment ~
Length and width of the rectangle measure :
[tex]\qquad \sf \dashrightarrow \:5 - ( - 4) = 9 \: units[/tex]
and
[tex]\qquad \sf \dashrightarrow \:0 - ( - 5) = 5 \: units[/tex]
Let's find the Perimeter ~
[tex]\qquad \sf \dashrightarrow \:2(9 + 5)[/tex]
[tex]\qquad \sf \dashrightarrow \:2(14)[/tex]
[tex]\qquad \sf \dashrightarrow \:28 \: units[/tex]
Now, find the Area of rectangle :
[tex]\qquad \sf \dashrightarrow \:9 \times 5[/tex]
[tex]\qquad \sf \dashrightarrow \:45 \:unit {}^{2} [/tex]
