O is the center of the regular nonagon below. Find its perimeter. Round to the nearest tenth if necessary.
17
O
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The perimeter of a nonagon is the sum of its side lengths
The perimeter of the regular nonagon is 840.7 units
The in-radius of the regular nonagon is given as:
r =17
The perimeter is then calculated as:
[tex]P = \frac{18r}{\tan(pi/9)}[/tex]
Substitute 17 for r
[tex]P = \frac{18 * 17}{\tan(pi/9)}[/tex]
Evaluate the product of 18 and 17
[tex]P = \frac{306}{\tan(pi/9)}[/tex]
Evaluate the quotient
[tex]P =840.7[/tex]
Hence, the perimeter of the regular nonagon is 840.7 units
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