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On the grid, A(-3,1), B(1,-2), and C(4,2) are connected. Kaire claims triangle ABC is a right isosceles triangle.​

On the grid A31 B12 and C42 are connected Kaire claims triangle ABC is a right isosceles triangle class=

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fieryanswererft

Answer:

  • Yes its an isosceles triangle but not a right angle triangle.

part A:

[tex]\sf AB^2 = (-2-1)^2 + (1+3)^2[/tex]

[tex]\sf AB^2 =25[/tex]

[tex]\sf AB =5[/tex]

[tex]\sf AC^2 = (2-1)^2 + (4+3)^2[/tex]

[tex]\sf AC^2 = 50[/tex]

[tex]\sf AC = 5\sqrt{2}[/tex]

[tex]\sf BC^2 = (2--2)^2 + (4-1)^2[/tex]

[tex]\sf BC^2 = 25[/tex]

[tex]\sf BC = 5[/tex]

Two sides are equal in the triangle of 5. Its an isosceles triangle.

part B:

if right angle triangle, then use the formula:

short side² + short side² = long side²

( 5√2 )² + 5² = ( 5√2 )²

75 = 50

Therefore, its not a right angle triangle.