Respuesta :
Percent decrease
= [(90-50) / 90 ] x 100%
= (40 / 90) x 100%
= 44.4%
= 44%
= [(90-50) / 90 ] x 100%
= (40 / 90) x 100%
= 44.4%
= 44%
- Initial temperature=t_i=90°C
- Final temperature=t_f=50°C
Total change in temperature
- ∆T=90-50=40°C
Percentage:-
[tex]\\ \sf\longmapsto \dfrac{\Delta T}{t_i}\times 100[/tex]
[tex]\\ \sf\longmapsto \dfrac{40}{90}\times 100[/tex]
[tex]\\ \sf\longmapsto \dfrac{400}{9}[/tex]
[tex]\\ \sf\longmapsto 44.4\%[/tex]