Respuesta :

nileshyadav85907

[tex]f(x) = 4x + k \\ \\ f(2) = f(1) \\ \\ now\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ solution : \: \: \: \: \: \: \: \: \: \\ \\ f(x) = 4x + 1 \\ \\ f(2) = 4(2) + k \\ \\ f(2) = 8 + k. \\ \\ f(1) = 4(1) + k \\ \\ f(1) = 4 + k \\ \\ 8+ k = 4 + k \\ \\ k - k = 4 -8 \\ \\ 0 = - 4[/tex]

The function has no solution.

f(x) = 4x + k

f(2) = f(1)

Therefore,

Function f(2):

f(2) = 4(2) + k

f(2) = 8 + k

Function f(1):

f(1) = 4(1) + k

f(1) = 4 + k

Recall f(2) = f(1),

Therefore,

8 + k = 4 + k

8 - 4 = k - k

4 = 0

There is no solution.

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