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DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

value of x is ~

[tex] \boxed{1}[/tex]

value of y is ~

[tex] \boxed{3}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

The first equation is ~

  • [tex]y = - x + 4[/tex]

now, let's substitute the value of y from the first equation into second one ~

  • [tex]y = 3x[/tex]

let's solve for value of x ~

  • [tex] - x + 4 = 3x[/tex]

  • [tex]3x + x = 4[/tex]

  • [tex]4x = 4[/tex]

  • [tex]x = 4 \div 4[/tex]

  • [tex]x = 1[/tex]

value of x = 1, now let's plug the value of x as 1 in the second equation to find the value of y ~

  • [tex]y = 3x[/tex]

  • [tex]y = 3 \times 1[/tex]

  • [tex]y = 3[/tex]

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