Answer:
See explanation for answer.
Step-by-step explanation:
Original equation: 2y^3-4x^2-4-1+3x^2-3y^3-y^3
= 2y^3 + −4x^2+ −4+ −1 + 3x^2+ −3y^3 + −y^3
= 2y^3 + −4x^2+ −4 + −1 + 3x^2+ −3y^3 + −y^3
= (2y^3 + −3y^3+ − y^3)+(−4x^2 + 3x^2)+(−4+ −1)
= −2y^3+ −x^2 + −5
Answer: = −2y^3 − x^2 − 5
I'm sorry if this is incorrect. I tried my best.
I hope I helped!
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