Pls help me with this!!1
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Answer:
Theoretical yield = 6.27
Percentage yield = 92%
Explanation:
2KOH + CO2 - K2CO3 + H2O
Theoretical yield =
Mr of 2KOH = 56g
5.09 / 56 = 0.09 moles of 2KOH
0.09 / 2 = 0.045 moles of K2CO3
Mr of K2CO3 = 138g
138 * 0.045 = 6.27
Percentage yield = 5.80/6.27 = 0.92
0.92 * 100 = 92%