What is the distance between the following points?
y
>
2 3 4 5 6 7 8 9
-2-
.
-4
-5
-6
-7+
-8
-9
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Point are
Using distance formula
[tex]\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{(8-2)^2+(-9+3)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{6^2+(-6)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{36+36}[/tex]
[tex]\\ \sf\longmapsto \sqrt{72}[/tex]
[tex]\\ \sf\longmapsto 8.2units[/tex]
[tex]\begin{gathered} {\underline{\boxed{ \rm {\red{ Distance \: = \: \sqrt{(x_2 \: - \: x_1) ^{2} \: + \:(y_2 \: - \: y_1)} }}}}}\end{gathered} [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: \sqrt{ \bigg(8 \: - \: 2 \bigg) ^{2} \: + \: \bigg( - 9 \: - \: (- 3) \bigg)^{2} } [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: \sqrt{ \bigg(8 \: - \: 2 \bigg) ^{2} \: + \: \bigg( - 9 \: + \: 3 \bigg)^{2} } [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: \sqrt{ (6 ) ^{2} \: + \:( - 6 )^{2} } [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: \sqrt{ (36 ) \: + \:( 36 ) } [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: \sqrt{72} [/tex]
[tex]\bf \longrightarrow \:Distance \: = \: 8.485281[/tex]
Approximate distance = 8.4
Hence , the distance between 2 points is
8.4 units