Suppose that the function h is defined, for all real numbers, as follows.
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Answer:
see explanation
Step-by-step explanation:
h(- 3) with x = - 3, that is x ≠ 1 , then
h(- 3) = - [tex]\frac{1}{2}[/tex] (- 3) + 2 = [tex]\frac{3}{2}[/tex] + 2 = [tex]\frac{7}{2}[/tex]
h(1) with x = 1 , then
h(1) = 1
h(3) with x = 3, that is x ≠ 1 , then
h(3) = - [tex]\frac{1}{2}[/tex] (3) + 2 = - [tex]\frac{3}{2}[/tex] + 2 = [tex]\frac{1}{2}[/tex]