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To indirectly measure the distance across a lake, Nachelle makes use of a couple landmarks at points D and E. She measures CF, FD, and FG as marked. Find the distance across the lake (DE), rounding your answer to the nearest hundredth of a meter

To indirectly measure the distance across a lake Nachelle makes use of a couple landmarks at points D and E She measures CF FD and FG as marked Find the distanc class=

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asuwafohjames

Answer:

207.68 m

Step-by-step explanation:

From the diagram,

ΔDEC is similar to ΔFGC

Therefore,

(DE)/(FG) = (DC)/(FC).............. Equation 1

make line DE the subject of the equation

DE = [(DC)(FG)/(FC)]................ Equation 2

From the diagram,

Given: DC = 190 m, FG = 142.1 m, FC = 130 m

Substitute these values into equation 2

DE = (190×142.1/130)

DE = 207.68 m

Hence the distance across the lake is 207.68 m

akposevictor

Applying the similarity theorem, the distance across the lake to the nearest hundredth is: DE = 207.68 m

Recall:

  • The corresponding side lengths of two triangles that are similar are always proportional to each other.

Thus:

ΔCDE  and ΔCFG are similar to each other

FG = 142.1 m

FC = 130 m

DF = 60 m

DC = 130 + 60 = 190 m

Therefore:

DE/FG = DC/FC

  • Substitute

DE/142.1 = 190/130

  • Cross multiply

[tex]DE = \frac{190 \times 142.1}{130} \\\\\mathbf{DE = 207.68 $ m}[/tex] (nearest hundredth).

Therefore, applying the similarity theorem, the distance across the lake to the nearest hundredth is: DE = 207.68 m

Learn more about similar triangles here: https://brainly.com/question/11899908

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