sin =9/15 . Find tan 0
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Answer:
c. 9/12
Step by step explanation.
Given: sin = 9/15
and,
[tex]sin = \frac{opp.}{hyp.} [/tex]
[tex]tan = \frac{opp.}{adj.} [/tex]
thus, find adj. side
by using Pythagoras theorem
[tex] {c }^{2} = {a}^{2} + {b}^{2} [/tex]
then,
let adj. side be a^
[tex] {a}^{2} = {c}^{2} - {b }^{2} \\ {a}^{2} = {15 }^{2} - {9}^{2} \\ {a}^{2} = 144 \\ a = 12[/tex]
thus,
adj. side is 12
then,
tan of the angle = 9/12