Find x. Using the image above.
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Answer:
[tex]adjacent = \frac{ 14 }{\sin(60 \degree)} \\ = 16.2 \\ x = \frac{adjacent}{ \cos(45 \degree) } \\ x = \frac{16.2}{ \cos(45 \degree)} \\ x = 22.9 \\ x \approx23[/tex]