Find the 8th term of the geometric sequence show below
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Answer:
8x^36
Step-by-step explanation:
first term (a) = [tex]8x^{8}[/tex]
Second term (t2)= [tex]8x^{12}[/tex]
common ratio (r)
= [tex]\frac{8x^{12} }{8x^{8} }[/tex]
= [tex]x^{4}[/tex]
now the 8th term of the G.S is
t8 = [tex]ar^{n-1}[/tex]
= [tex]8x^8 * (x^4)^8^-^1[/tex]
= [tex]8x^8 * (x^4)^7\\[/tex]
= [tex]8x^8 *x^2^8\\= 8x^3^6[/tex]
hope it will help