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a car is traveling at 20m/s along a road. a child runs out into the road 50 m ahead and the car driver steps on the break. what must the car's decelaration be if the car is to stop just before it reaches the child.

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jay40891

Answer:

4 m/s²

Explanation:

[tex]v {}^{2} = {u}^{2} + 2as \\ 0 {}^{2} = {20}^{2} + 2a(50) \\ a = - 4ms {}^{ - 2} [/tex]

Therefore, deceleration = 4 m/s²

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