Given that triangle ABC ~ XYZ, AB= 4,XY=3,and XZ= 5, find AC

Answer:
[tex]AC = \frac{20}{3}[/tex]
Step-by-step explanation:
Given
[tex]AB = 4[/tex]
[tex]XY = 3[/tex]
[tex]XZ = 5[/tex]
Required
Find AC
ABC XYZ
To solve AC, we make use of the following equivalent ratios.
[tex]AB : AC = XY : XZ[/tex]
This gives:
[tex]4 : AC = 3 : 5[/tex]
Express as fraction
[tex]\frac{4 }{ AC }= \frac{3 }{ 5}[/tex]
Cross multiply
[tex]3 * AC = 4 * 5[/tex]
[tex]3 * AC = 20[/tex]
Solve for AC
[tex]AC = \frac{20}{3}[/tex]